Thread Killer Mk VII

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sycogrim said:
To me how I see it is you're shaving off about 9cm worth of the bar which unless I'm wrong it works out to be 3.375kg and at 22.5% loss.

This is how I got that but I could be wrong:


Length + Width + Depth = 40cm total

15kg / 40cm = 0.375g per 1cm

1.5cm * 4 = 9cm total cut at 110 degrees

0.375g * 9cm = 3.375kg taken

3.375kg * 100 / 15kg = 22.5%

I dunno...
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look at Syco pretending he knows math and shit. who in the office helped you with this one mike? Connie in accounting? Edward from HR? :p
 
sycogrim said:
To me how I see it is you're shaving off about 9cm worth of the bar which unless I'm wrong it works out to be 3.375kg and at 22.5% loss.

This is how I got that but I could be wrong:


Length + Width + Depth = 40cm total

15kg / 40cm = 0.375g per 1cm

1.5cm * 4 = 9cm total cut at 110 degrees

0.375g * 9cm = 3.375kg taken

3.375kg * 100 / 15kg = 22.5%

I dunno...
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Never enjoyed maths here so how did you figure that out :D

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Murph said:
It's too early for maths.
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isn't any time too early :p
 
MalicE said:
look at Syco pretending he knows math and shit. who in the office helped you with this one mike? Connie in accounting? Edward from HR? :p
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loooooooooooooooooooooool thanks you ass, at least I tried :o I don't see any of you lazy fsckers trying

Ichigo said:
Never enjoyed maths here so how did you figure that out :D

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isn't any time too early :p
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I just started drawing and playing around on various ideas, mostly possibilities of what it could be etc... Like I said I could be wrong but that was my conclusion.
 
DCWarhound said:
Need a little math help.

You have a copper plate ingot with the dimensions:
Length:20cm
Width:14cm
Thickness:6cm

And a weight of 15KG's

1.5cm from the top you cut off 4 pieces from the sides at a 110' angle.

How much does the ingot weigh and how much percentage was removed from it's overall weight?
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I love math, so here is my attempt at cracking this...the end result is 12.77kg left on the ingot, which is a loss of 14.866%

equations1.jpg
equations2.jpg
 
sycogrim said:
To me how I see it is you're shaving off about 9cm worth of the bar which unless I'm wrong it works out to be 3.375kg and at 22.5% loss.

This is how I got that but I could be wrong:


Length + Width + Depth = 40cm total

15kg / 40cm = 0.375g per 1cm

1.5cm * 4 = 9cm total cut at 110 degrees

0.375g * 9cm = 3.375kg taken

3.375kg * 100 / 15kg = 22.5%

I dunno...
Click to expand...

Woah,odd method though.

How did you work out this part though?
1.5cm * 4 = 9cm total cut at 110 degrees
Click to expand...

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DieGrootH@mmer said:
I love math, so here is my attempt at cracking this...the end result is 12.77kg left on the ingot, which is a loss of 14.866%

View attachment 7056
View attachment 7057
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Thats awesome.

Will try and study it :)
 
Suddenly feel awkward with all these clever math-koppies around.... At least we try and cure cancer! Lol.



Anywayzzzz question please.......
 
Ichigo said:
If I had an Iphone I would since I love my S4 so much and the pictures it takes :D.
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You see this I get a lot. But you don't have an iphone so you won't know the difference. Lol!

I need someone who went from the one to the other....
 
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