FriedPet
New member
six - 9(ix) = s
9(ix) - 10(x) = i
40(xl) - 50(l) = x
That's it.
It's been years since I did maths...care to explain a little bit more...?
six - 9(ix) = s
9(ix) - 10(x) = i
40(xl) - 50(l) = x
That's it.
What starts with E and ends with E but only has 1 Letter in it
It has six faces and twelve edges too
It has six colors one of which is blue.
It can twist and turn, keeping you amused
Until all is whole you may be confused
What is it?
A Rubick's cube?
They're all closed except door one?
I used my calendar to calculate the first 20 doors. I found that all the square numbers will be open, meaning: 1, 4, 9, 16, 25, 36, 49, 64, 81 and 100 will be open. Correct?
Edit: I see now that there is 1000 doors...
Open doors:
1,4,9,16,25,36,49,64,81,100,121,144,169,196,225,256,289,324,361,400,441,484,529,576,625,676,729,784,841,900,961
Hope that's all...
Correct Neb! Well done on getting that one, I thought it was a real b****!
You're up.
It was! At first glance I ignored the riddle as it looked too difficult, but as I was studying last night I thought this looked more interesting!![]()
I found this one on the internet, too lazy to figure it out.
Chris Mercer informed me that in Germany there are calendars made of wooden blocks for very bright kids.
There are two six sided dice, and by choosing which face is displayed for the two of these, all possible monthly dates (from 01, 02, …, to 29, 30, 31) can be displayed; note the single digit dates must start with a 0.
Your job is to write one digit (from 0, 1, 2, …, 8, 9) on each face of the two dice so that this can be done. Good luck!
Both dice need 0 to 3 on i.e. 0,1,2,3. That leaves 2 empty sides on each die. On the one die, you can write 5 and 6 and on the other you can write 7 and 8. If you place the first die upside-down on the 6, it acts as a 9, and if you place the second die upside-down on the 7 is acts a 4. If it makes you happier it can be a 4 that acts a 7 when upside down, but either way, it works.
Surely only one dice needs a zero since you don't have a 00 date but you do get 11, 22, 33 so the dice needs to be 0, 1, 2, 3, 4, 5 and 1, 2 ,3, 6, 7, 8 with six doubling as 9 also?
Surely only one dice needs a zero since you don't have a 00 date but you do get 11, 22, 33 so the dice needs to be 0, 1, 2, 3, 4, 5 and 1, 2 ,3, 6, 7, 8 with six doubling as 9 also?