Riddle me this, Riddle me that!
- Thread starter Roomys
- Start date
Roomys
Will post for beer
MetalSoup
There's a GIF for that
That's kind of silly if you consider how force works. He would probably break the bridge anyway.
Roomys
Will post for beer
Mister 44
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You don't know the power of the dark side.
unstablebob
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an old easy one:
I have many teeth but never eat, speak or need food, what am I
I have many teeth but never eat, speak or need food, what am I
unstablebob
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never thought of that really, not the answer i had in mind though
StaggerLee
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MetalSoup
There's a GIF for that
This has nothing to do with the big bang theory, it's fairly simple laws of physics.
unstablebob
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thats the answer i had in mind, congrats
StaggerLee
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Great.
This is my favourite riddle of all time, it may have already appeared here:
Suppose you’re on a game show, and you’re given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat. He then says to you, “Do you want to pick door No. 2?†Is it to your advantage to switch your choice?
This is my favourite riddle of all time, it may have already appeared here:
Suppose you’re on a game show, and you’re given the choice of three doors: Behind one door is a car; behind the others, goats. You pick a door, say No. 1, and the host, who knows what’s behind the doors, opens another door, say No. 3, which has a goat. He then says to you, “Do you want to pick door No. 2?†Is it to your advantage to switch your choice?
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Roomys
Will post for beer
StaggerLee
New member
If you and Roomys really want to go into this as a discussion, then follow this link:
http://physics.stackexchange.com/qu...uce-the-total-weight-of-the-juggler-and-balls
Roomys
Will post for beer
None of that needed, my Question about him being serious was in reference to his "This is has nothing to do with the big bang theory" And missing my meme joke all together about the series. Is it possible he doesnt know how frightful a ladybug is?
MetalSoup
There's a GIF for that
I don't watch TV. We are going way off topic now though.
unstablebob
New member
yes it is, its got to do with variable change.
StaggerLee
New member
Isn't all change variable
This is unfortunately not a yes or no riddle, you sort of have to justify your answer...
unstablebob
New member
Isn't all change variable
This is unfortunately not a yes or no riddle, you sort of have to justify your answer...
you start off with 3 choices so you have 33.333333% chance of winning, they remove one option now if you change you have 50% of winning. So by changing your choice your chance of winning increased by 16.66666%
StaggerLee
New member
You are on the right track, and this is actually a very difficult probability theory problem. I am going to give it to you anyway because it's difficult.
You are actually increasing your chances to 66.66666~%. So you DOUBLE your chances by changing. The simplest way to look at this is to say that when you start, you have a 33.3333~% chance of winning and a 66.6666~% chance of losing. Once you choose one door and the host reveals a goat behind one of the doors, they are removing that loss from the equation. Now, if you change, you change an initial loss into a win, and an initial win into a loss, in other words the initial probabilities reverse, and you double your odds. So, statistically speaking, you should change.
For a more in-depth analysis of the problem, if anyone actually gives a crap or doesn't believe me, go here:
http://en.wikipedia.org/wiki/Monty_Hall_problem
And for a more technical analysis:
http://formalisedthinking.wordpress.com/2010/10/05/bayes-theorem-and-the-monty-hall-problem/
Right unstablebob, you're up.